0 Deepak BoraNewbie Asked: July 26, 20202020-07-26T20:33:19+05:30 2020-07-26T20:33:19+05:30In: CBSE Two right triangles ABC and DBC are drawn on the same hypotenuse BC and on the same side of BC. If AC and BD intersect at P, prove that AP × PC = BP × DP. 0 CBSE 10th Class past year question paper Year 2019 SET 1, Code Number- 30/2/1 Question number – 14 (a) cbse 10th classncert classprevious year paper Share Facebook 2 Answers Voted Oldest Recent Kush 2022-03-05T21:44:18+05:30Added an answer on March 5, 2022 at 9:44 pm Angle A = angle D……( 90 degrees given) Angle APB= angle DPC…..(VERTICALLY OPPOSITE ANGLES) Therefore, APB similar to triangle DPC…(by AA rule) Therefore, AP/DP=BP/PC So,AP×PC=BP×DP HENCE,PROVED. 2 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Deepak Bora Newbie 2020-07-29T07:48:22+05:30Added an answer on July 29, 2020 at 7:48 am ∆APB ~ ∆DPC [AA similarity] AP/DP =BP/PC AP × PC = BP × DP 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions A hemispherical tank, full of water, is emptied by a pipe at the rate of 25/7 litres per ... The radius and height of a solid right-circular cone are in the ratio of 5 : 12. If ... Find the mode of the following distribution Check whether 12∧n can end with the digit 0 for any natural number n. 12∧n = (2 × ... The distance between the points (m, -n) and (-m, n) is

Angle A = angle D……( 90 degrees given)

Angle APB= angle DPC…..(VERTICALLY OPPOSITE ANGLES)

Therefore, APB similar to triangle DPC…(by AA rule)

Therefore, AP/DP=BP/PC

So,AP×PC=BP×DP

HENCE,PROVED.

∆APB ~ ∆DPC [AA similarity]

AP/DP =BP/PC

AP × PC = BP × DP