This an important question for the cbse and ncert exam. question from RS Aggarwal book, Mensuration chapter, Volume and Surface Area of Solids; Exercise 17A; page number 786.
This question ask in 2014 and 2011 board exam. This question based on Volume and area of solids.
volume of a cube = 27 cm³
volume of a cube = (edge)³
27 = (edge)³
³√27 = edge
∴ edge = 3 cm
The length of the resulting cuboid,
l = 3 +3 = 6 cm,
its breadth,
b = 3 cm
and its height,
h = 3 cm
Surface area cuboid = 2 ( [length × breadth ] + [breadth × height] + [height × length ] )
∴ Surface area of resulting cuboid is = 2 (lb + bh + hl)
= 2 ( [6×3] + [3×3] + [3×6] )
= 2 × 45
= 90
∴ Surface area of resulting cuboid is 90 cm²