This an important question for the cbse and ncert exam. question from RS Aggarwal book, Mensuration chapter, Volume and Surface Area of Solids; Exercise 17A; page number 786.

This question ask in 2014 and 2011 board exam. This question based on Volume and area of solids.

volume of a cube = 27 cm³

volume of a cube = (edge)³

27 = (edge)³

³√27 = edge

∴ edge = 3 cm

The length of the resulting cuboid,

l = 3 +3 = 6 cm,

its breadth,

b = 3 cm

and its height,

h = 3 cm

Surface area cuboid = 2 ( [length × breadth ] + [breadth × height] + [height × length ] )

∴ Surface area of resulting cuboid is = 2 (lb + bh + hl)

= 2 ( [6×3] + [3×3] + [3×6] )

= 2 × 45

= 90

∴ Surface area of resulting cuboid is 90 cm²