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Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the distance between AB and CD is 6 , find the radius of the circle. Q.2

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What is the easiest way for solving the question of class 9th ncert math of exercise 10.6of math of Circles chapter of question no. 2  Please help me for the best suggestion of this question Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the distance between AB and CD is 6 , find the radius of the circle.

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  1. Ncert solutions class 9 chapter 10-30

    Here, OM ⊥ AB and ON ⊥ CD. is drawn and OB and OD are joined.

    We know that AB bisects BM as the perpendicular from the centre bisects chord.

    Since AB = 5 so,

    BM = AB/2

    Similarly, ND = CD/2 = 11/2

    Now, let ON be x.

    So, OM = 6−x.

    Consider ΔMOB,

    OB2 = OM2+MB2

    Or,

    Ncert solutions class 9 chapter 10-31

    Consider ΔNOD,

    OD2 = ON2 + ND2

    Or

    Ncert solutions class 9 chapter 10-32

    We know, OB = OD (radii)

    From equation 1 and equation 2 we get

    Ncert solutions class 9 chapter 10-33

    Now, from equation (2) we have,

    OD2= 12 +(121/4)

    Or OD = (5/2)×√5 cm

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