In the given question we are to find the length of EF by using the properties of similarities, if the area of △ABC is 16 cm 2 , and that of △DEF 25 cm 2 . If BC=2.3 cm
ML Aggarwal Avichal Publication, chapter 13.3, Similarity, question no 2
Rajan@2021Guru
Triangles ABC and DEF are similar .The area of △ABC is 16 cm 2 , and that of △DEF 25 cm 2 . If BC=2.3 cm, find EF
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Ratio of area is equal to square of ratios of its corresponding sides
Hence, ΔABC/ΔDEF=(BC/EF)2
16/25=2.3×2.3/EF^2
EF=√8.265625
∴ EF=2.875cm