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Deepak BoraNewbie
The vertices of a triangle ABC are (3,8) , B(-1,2), C(6-6). Find: 1. The slope of BC , 2.Equation of a line perpendicular to BC and passing through A
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(1) Slope of BC, B(-1,2), C(6,-6)
m= y2-y1/x2-x1
m= -6-2/6+1
= -8/7
(2)
Let AD⊥ BC
(slope of AC)( slope of BC) = -1
(m1)(-8/7) = -1
(m1) = 7/8
And AD is passing through A(3,8)
equation of a line
(y-y1)= m1(x – x1)
y-8= 7/8(x-3)
8y-64= 7x-21
7x-8y+43=0