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Deepak Bora
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Asked: 2020-09-25T15:06:14+05:30 In:

The radius of the base of a right circular cylinder is halved and the height is doubled. What is the ratio of the volume of the new cylinder to that of the original cylinder?

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ICSE Board Question Based on Mensuration Chapter of M.L Aggarwal for class10
In this question the radius of the base of a right circular cylinder is halved and the height is doubled. What will be the ratio of the volume of the new cylinder to that of the original cylinder?
This is the Question Number 13, Exercise 17.1 of M.L Aggarwal.

chapter 17 mensurationicseml aggarwal class 10
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    1. This answer was edited.

      Let the radius of the base of a right circular cylinder be r and height be h.

      Volume of the cylinder, V1 = πr2h

      The radius of the base of a right circular cylinder is halved and the height is doubled.

      So radius of new cylinder = r/2

      Height of new cylinder = 2h

      Volume of the new cylinder, V2 = πr2h

      = π(r/2)2 ×2h

      = ½ πr2h

      So ratio of volume of new cylinder to the original cylinder , V2/V1= ½ πr2h/πr2h = ½

      Hence the required ratio is 1:2.

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