ICSE & CBSE Board Question Based on Arithmetic Progression of RS Aggarwal

Here An AP in the form of Production of TV is given Here the act of 6th and 9th term is given

You have to find the production in

(i)first year

(ii)8th year

(iii)6th year

This is the Question Number 33 Of Exercise 11 C of RS Aggarwal Solution.

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# The production of a TV in a factory increases uniformly by a fixed number every year. It produced 8000 acts in 6th year and 11300 in 9th year. Find the production in (i) first year (ii) 8th year (iii)6th year Hint = S_n=n/2(a+l)=6/2(2500+8000)=31500

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According to the question

Solution :-

x+5y=8000

x+8y=11300

Solving the two will give you y=1100

Putting the value of d in any of the equations

will give x=2500

(a) 2500

(b) x+7y=2500+7Ã—1100=10200

(6) x+5y=2500+5Ã—1100=8000