Give me the best way for solving the question of class 9th of Surface areas and Volumes of exercise 13.6 of math. Give me the easiest way for solving this question in simple way of question no.2 The inner diameter of a cylindrical wooden pipe is 24cm and its outer diameter is 28 cm. The length of the pipe is 35cm.Find the mass of the pipe, if 1cm3 of wood has a mass of 0.6g. (Assume π = 22/7)
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The inner diameter of a cylindrical wooden pipe is 24cm and its outer diameter is 28 cm. The length of the pipe is 35cm.Find the mass of the pipe, if 1cm3 of wood has a mass of 0.6g. (Assume π = 22/7) Q.2
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Inner radius of cylindrical pipe, say r1 = diameter1/ 2 = 24/2 cm = 12cm
Outer radius of cylindrical pipe, say r2 = diameter2/ 2 = 28/2 cm = 14 cm
Height of pipe, h = Length of pipe = 35cm
Now, the Volume of pipe = π(r22-r12)h cm3
Substitute the values.
Volume of pipe = 110×52 cm3 = 5720 cm3
Since, Mass of 1 cm3 wood = 0.6 g
Mass of 5720 cm3 wood = (5720×0.6) g = 3432 g or 3.432 kg. Answer!