Yesterday i was doing the question of class 10th ncert of statistics of exercise 14.2 of question no,5 sir how i solve this tough question give me the best way to solve this problem The given distribution shows the number of runs scored by some top batsmen of the world in one- day international cricket matches
Given data:
Modal class = 4000 – 5000,
l = 4000,
class width (h) = 1000,
fm = 18, f1 = 4 and f2 = 9
Mode Formula:
Mode = l+ [(fm-f1)/(2fm-f1-f2)]×h
Substitute the values
Mode = 4000+((18-4)/(36-4-9))×1000
Mode = 4000+(14000/23) = 4000+608.695
Mode = 4608.695
Mode = 4608.7 (approximately)
Thus, the mode of the given data is 4608.7 runs