ICSE & CBSE Board Question Based on Linear Equations in two Variables of RS Aggarwal
Here the denominator of a fraction is greater than its numerator by the given number. if a number is added to both its numerator and denominator, it becomes 3/4.
You have to find the fraction.
This is the Question Number 21 Of Exercise 3E of RS Aggarwal Solution.
Deepak BoraNewbie
The denominator of a fraction is greater than its numerator by 11. if 8 is added to both its numerator and denominator, it becomes 3/4. Find the fraction.
Share
Let the required fraction be x/y .
According to the Question
1st Equation
⇒ y = x + 11
⇒ y – x = 11 ……(i)
2nd Equation
⇒ x+8/y+8 = 3/4
⇒ 4(x + 8) = 3(y + 8)
⇒ 4x+ 32 = 3y + 24
⇒ 4x – 3y = -8 ……(ii)
On multiplying Equation(i) by 4
4y – 4x = 44
On adding Eq (ii) and (iii)
⇒ y = (-8 + 44)
⇒ y = 36
on substituting y = 36 in (i), we get:
⇒ y – x = 11
⇒ 36 – x = 11
⇒ x = (36 – 11)
⇒ x = 25
Hence, the required fraction is 25/36