What is the best way for solving the question from class 9^{th} ncert math of Surface areas and Volumes chapter of Ncert of exercise 13.2 of math. What is the best way for solving this question please guide me the best way for solving this question no .1 The curved surface area of a right circular cylinder of height 14 cm is 88 cm2. Find the diameter of the base of the cylinder. (Assume π =22/7 )

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# The curved surface area of a right circular cylinder of height 14 cm is 88 cm2. Find the diameter of the base of the cylinder. (Assume π =22/7 ) Q.1

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Height of cylinder, h = 14cm

Let the diameter of the cylinder be d

Curved surface area of cylinder = 88 cm

^{2}We know that, formula to find Curved surface area of cylinder is 2πrh.

So 2πrh =88 cm

^{2}(r is the radius of the base of the cylinder)2×(22/7)×r×14 = 88 cm

^{2}2r = 2 cm

d =2 cm

Therefore, the diameter of the base of the cylinder is 2 cm.

## The curved surface area of a right circular cylinder of height 14 cm is 88cm^2 . Find diameter of the cylinder.(π=22/7).