An Important Question of class 10 Based on Section Formula Chapter of M.L Aggarwal for ICSE BOARD.
Here two co-ordinates points are given and ration of sides are given .
Solve this question.
This is the Question Number 02, Exercise 11 of M.L Aggarwal.
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The co-ordinates of two points A and B are ( – 3, 3) and (12, – 7) respectively. P is a point on the line segment AB such that AP : PB = 2 : 3. Find the co-ordinates of P.
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Let the co-ordinates of P(x, y) divides AB in the ratio m:n.
A(-3,3) and B(12,-7) are the given points.
Given m:n = 2:3
x1 = -3 , y1 = 3 , x2 = 12 , y2 = -7 , m = 2 and n = 3
By Section formula x = (mx2+nx1)/(m+n)
x = (2×12+3×-3)/(2+3)
x = (24-9)/5
x = 15/5
x = 3
By Section formula y = (my2+ny1)/(m+n)
y = (2×-7+3×3)/5
y = (-14+9)/5
y = -5/5
y = -1
Hence the co-ordinate of point P are (3,-1).