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AnilSinghBora
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Asked: 2021-07-28T13:38:16+05:30 In:

The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower. Q.4

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Please suggest me the best solution of the question from class 10th of Applications of Trigonometry of exercise 9.1 of class 10th of question no.4. Give me the best solution for this question because it is very important for class 10th, The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower.

best math ncert solutionexercise 9.1 ncertncert class 10th solutionsome applications of trigonometry ncert
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    1. Guru

      Let AB be the height of the tower and C is the point elevation which is 30 m away from the foot of the tower.

      C:\Users\User\Desktop\NCERT\images\tri4.jpg

      To Find: AB (height of the tower)

      In right ABC

      tan 30° = AB/BC

      1/√3 = AB/30

      ⇒ AB = 10√3

      Thus, the height of the tower is 10√3 m.

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