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deepaksoni
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The angle of elevation of the top of a tower from a point on the ground and at a distance of 150 m from its foot is 300. Find the height of the tower correct to one place of decimal.

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sir this is the question from the book -ML aggarwal( avichal publication) class 10th , chapter20 , heights and distances
we have the data that :- The angle of elevation of the top of a tower from a point on the ground and at a distance of 150 m from its foot is 300.
Now we have to find the  height of the tower correct to one place of decimal.
This is a very important question
question no 2 , heights and distances , ICSE board

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1 Answer

  1. Consider BC as the tower and A as the point on the ground such that

    ∠A = 300 and AC = 150 m

    ML Aggarwal Solutions for Class 10 Chapter 20 Image 2

    Take x m as the height of the tower

    We know that

    tan θ = BC/AC

    Substituting the values

    tan 300 = x/150

    By cross multiplication

    1/√3 = x/150

    So we get

    x = 150/√3

    Multiplying and dividing by √3

    x = (150 × √3)/ (√3 × √3)

    By further calculation

    x = 150√3/ 3 = 50√3 m

    Substituting the value of √3

    x = 50 (1.732)

    x = 86.600 m

    x = 86.6 m

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