sir this is the question from the book -ML aggarwal( avichal publication) class 10th , chapter20 , heights and distances
we have the data that :- The angle of elevation of the top of a tower from a point on the ground and at a distance of 150 m from its foot is 300.
Now we have to find the height of the tower correct to one place of decimal.
This is a very important question
question no 2 , heights and distances , ICSE board
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The angle of elevation of the top of a tower from a point on the ground and at a distance of 150 m from its foot is 300. Find the height of the tower correct to one place of decimal.
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Consider BC as the tower and A as the point on the ground such that
∠A = 300 and AC = 150 m
Take x m as the height of the tower
We know that
tan θ = BC/AC
Substituting the values
tan 300 = x/150
By cross multiplication
1/√3 = x/150
So we get
x = 150/√3
Multiplying and dividing by √3
x = (150 × √3)/ (√3 × √3)
By further calculation
x = 150√3/ 3 = 50√3 m
Substituting the value of √3
x = 50 (1.732)
x = 86.600 m
x = 86.6 m