Adv
Deepak Bora
  • 1

Sum of the areas of two squares is 544 m² . If the difference of their perimeter is 32 m, find the sides of the two squares.

  • 1

CBSE 10th Class Mathematics
Past year question paper
Year 2020
SET 1, Code Number  – 30/5/1
Question Number –  37 [a]
area and perimeter relation
use area and perimeter formula

Share

Related Questions

Adv

1 Answer

  1. Let the sides of the two squares be x and y (x > Y)

    Difference in perimeter is = 32

    4x – 4y = 32

    x – y = 8

    y = x – 8

    Sum of area of two squares = 544

    x² + y² = 544

    x² + (x – 8)² = 544

    x² + x² + 64 – 16 x = 544

    2x² – 16x = 480

    x² – 8x = 240

    x² – 8x – 240 = 0

    (x – 20) (x + 12) = 0

    X = 20,- 12

    Side can’t be negative.

    So x = 20

    y = x – 8 = 20 – 8 = 12

    ∴ Sides of squares are 20 cm, 12cm

    • 0
Leave an answer

Leave an answer

Browse

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Captcha Click on image to update the captcha.