Solution:

Given,

x + y = 3……. (i)

2x + 5y = 12……. (ii)

For equation (i),

When y = 0, we have x =3

When x= 0, we have y =3

Thus, we have the following table giving points on the line x + y = 3

x	0	3
y	3	0

For equation (ii),

We solve for y:

⇒ y = (12 – 2x)/5

So, when x = 1

y = (12 – 2(1))/5 = 2

And, when x = 6

⇒ y = (12 – 2(6))/5 = 0

Thus, we have the following table giving points on line 2x + 5y = 12

x	1	6
y	2	0

Graph of the equations (i) and (ii) is as below:

Clearly, the two lines intersect at a single point P (1, 2).

Hence, x= 1 and y = 2