One of the most important and conceptual question from quadratic equation chapter in which we have been asked to solve the equation √7x²-6x-13√7=0
Kindly solve the above problem in detail
RS Aggarwal, Class 10, chapter 4A, question no 24
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√7x²−6x−13√7=0
√7x²+7x−13x−13√7=0
√7x(x+√7)−13(x+√7)=0
(x+√7)(√7x−13)=0
Either x+√7=0, then x=−√7
or √7x−13=0, then √7x=13
x=−7 or 13√7/7