Sir please give me a detailed solution of these questions
2x-3y+4=0, x+2y-5=0
In the given equations we have to solve the equations graphically and also asked to find the vertices and the area of the triangle formed by these lines and the x-axis
RS Aggarwal, Class 10, chapter 3A, question no 12
2x−3y+4=0….(1)
x+2y−5=0……(2)
Isolate x from equation (1) and find the value of x and y.
2x−3y+4=0
or x=(3y−4)/2
Similarly, isolate x from equation (2) and find the values of x and y.
x+2y−5=0
or x=5−2y
Graph:
Now,
Find the area of triangle BAD:
Area of △BAD=1/2(base×altitude)
=1/2×7×2
=7 sq.units.