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Solve for x and y: 2x+3y=0, 3x+4y=5

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This question is from linear equations in two variables in which we have to find the value of x and y from the equations 2x+3y=0, 3x+4y=5

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RS Aggarwal, Class 10, chapter 3B, question no 3

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  1. The given system of equation is:  2x + 3y = 0 ……(i)  3x + 4y = 5 ……(ii)  On multiplying (i) by 4 and (ii) by 3, we get:  8x + 12y = 0 ……(iii)  9x + 12y = 15 …….(iv)  On subtracting (iii) from (iv) we get: x = 15  On substituting the value of x = 15 in (i), we get:  30 + 3y = 0  ⇒3y = -30  ⇒y = -10  Hence, the solution is x = 15 and y = -10.

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