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Sides of two similar triangles are in the ratio 4 : 9. Areas of these triangles are in the ratio (A) 2 : 3 (B) 4 : 9 (C) 81 : 16 (D) 16 : 81 Q.9

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The important question of class 10th of chapter triangles of exercise 6.4, what is the simple method to solve this question Sides of two similar triangles are in the ratio 4 : 9. Areas of these triangles are in the ratio (A) 2 : 3 (B) 4 : 9 (C) 81 : 16 (D) 16 : 81

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  1. Given, Sides of two similar triangles are in the ratio 4 : 9.

    Triangles Exercise 6.4 Answer 9

    Let ABC and DEF are two similar triangles, such that,

    ΔABC ~ ΔDEF

    And AB/DE = AC/DF = BC/EF = 4/9

    As, the ratio of the areas of these triangles will be equal to the square of the ratio of the corresponding sides,

    ∴ Area(ΔABC)/Area(ΔDEF) = AB2/DE

    ∴ Area(ΔABC)/Area(ΔDEF) = (4/9)= 16/81 = 16:81

    Hence, the correct answer is (D).

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