Solution: 

Given that,

A₁₀ = 41 and a₁₈ = 73

As we know that, to find nth term in an A.P = a + (n – 1)d

therefore,

a₁₀ = a + (10 – 1)d

= a + 9d = 41 ———(i)

Similarly,

a₁₈ = a + (18 – 1)d

= a + 17d = 73 ——-(ii)

Solving (i) and (ii),

(ii) – (i)

a + 17d – (a + 9d) = 73 – 41

8d = 32

d = 4

Using d in (i), we get

a + 9(4) = 41

a = 41 – 36 = 5

Now, the 26th term is given by a26 = 5 + (26 – 1)4 = 5 + 100 = 105

Hence the 26th term is 105.