This is the basic and conceptual question from Chapter name- Arithmetic Progression
Chapter number- 9
Exercise 9.6
In this question we have been given an arithmetic progression having nth term as xn = 6 – n
And we have to find its sum of first 15 terms.
CBSE DHANPAT RAI publications
Class:- 10th
Solutions of CBSE Mathematics
Question 5(iii)
Given A.P. has nth term, an = 6 – n
and number of terms(n) = 15
So, an = 6 – n = -9
On putting n = 1, we get a, first term of the A.P.,
a = 6 – 1 = 5
S15 = n[a + an]/2
= 15(5 – 9)/2 = 15 x (-2) = -30
Hence, the sum of the first 15 terms of given A.P. is -30.