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Question 5. (a) In the figure (i) given below, ABCD is a parallelogram. A circle passes through A and D and cuts AB at E and DC at F. Given that ∠BEF = 80°, find ∠ABC. (b) In the figure (ii) given below, ABCD is a cyclic trapezium in which AD is parallel to BC and ∠B = 70°, find: (i)∠BAD (ii) DBCD.

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This is circle based question from Chapter name- circles
Topic – Angle properties of circles
Chapter number- 15

In this question we have been given the information about the angles and we have to find the value of angles asked in question.
ICSE Avichal publication
Understanding ICSE Mathematics
Question no 5

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  1. Solution:
    (a) ADFE is a cyclic quadrilateral
    Ext. ∠FEB = ∠ADF
    ⇒ ∠ADF = 80°
    ABCD is a parallelogram
    ∠B = ∠D = ∠ADF = 80°
    or ∠ABC = 80°
    (b)In trapezium ABCD, AD || BC
    (i) ∠B + ∠A = 180°
    ⇒ 70° + ∠A = 180°
    ⇒ ∠A = 180° – 70° = 110°
    ∠BAD = 110°
    (ii) ABCD is a cyclic quadrilateral
    ∠A + ∠C = 180°
    ⇒ 110° + ∠C = 180°
    ⇒ ∠C = 180° – 110° = 70°
    ∠BCD = 70°

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