This is the basic and conceptual question from Chapter name- Arithmetic Progression
Chapter number- 9
Exercise 9.6
In this question we have been given that In an A.P. , the first term is 2, the last term is 29 and the sum of the terms is 155.
Now we have to find the common difference of the A.P.
CBSE DHANPAT RAI publications
Class:- 10th
Solutions of CBSE Mathematics
Question 35
Given A.P. has first term(a) = 2, last term(an) = 29 and sum(Sn) = 155.
By using the formula of the sum of first n terms of an A.P.
Sn = n[a + an] / 2.
=> 155 = n(2 + 29) / 2
=> 31n = 310
=> n = 10
By using the formula of nth term of an A.P.
an = a + (n – 1)d
So,
=> 29 = 2 + (10 – 1)d
=> 9d = 27
=> d = 3
Hence, the common difference of the A.P. is 3.