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Question 33. (a) In the figure (i) given below, PAB is secant and PT is tangent to a circle. If PA : AB = 1:3 and PT = 6 cm, find the length of PB. (b) In the figure (ii) given below, ABC is an isosceles triangle in which AB = AC and Q is mid-point of AC. If APB is a secant, and AC is tangent to the circle at Q, prove that AB = 4 AP

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This is the basic and conceptual question from Chapter name- circles
Topic – Angle properties of circles
Chapter number- 15

In this question we have a figure(i)

in which , PAB is secant and PT is tangent to a circle.

It is given that PA : AB = 1:3 and PT = 6 cm, now we have to find the length of PB.

(b) In the figure (ii) given in the question ABC is an isosceles triangle in which AB = AC and Q is mid-point of AC.

APB is a secant, and AC is tangent to the circle at Q,

Now we are asked to prove that AB = 4 AP

ICSE Avichal publication
Understanding ICSE Mathematics
Question 33

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1 Answer

  1. Solution:
    (a) In the figure (i),
    PAB is secant and PT is the tangent to the circle.
    PT² = PA × PB
    ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 15 Circles Ex 15.3 Q33.2
    ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 15 Circles Ex 15.3 Q33.3

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