This is the basic and conceptual question from Chapter name- circles
Topic – Angle properties of circles
Chapter number- 15
In this question we have a figure(i)
in which , PAB is secant and PT is tangent to a circle.
It is given that PA : AB = 1:3 and PT = 6 cm, now we have to find the length of PB.
(b) In the figure (ii) given in the question ABC is an isosceles triangle in which AB = AC and Q is mid-point of AC.
APB is a secant, and AC is tangent to the circle at Q,
Now we are asked to prove that AB = 4 AP
ICSE Avichal publication
Understanding ICSE Mathematics
Question 33
Solution:
(a) In the figure (i),
PAB is secant and PT is the tangent to the circle.
PT² = PA × PB