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deepaksoni
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Asked: 2021-03-26T17:48:23+05:30 In:

Ques 20(b) In the figure (ii) given below, chords BA and DC of a circle meet at P. Prove that: (i) ∠PAD = ∠PCB (ii) PA. PB = PC . PD.

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Ques 20(b) In the figure (ii) given below, chords BA and DC of a circle meet at P. Prove that: (i) ∠PAD = ∠PCB (ii) PA. PB = PC . PD.

This is an important and exam oriented question from Chapter name- circles
Topic – Angle properties of circles
Chapter number- 15

It is given that in a circle , chords BA and DC of a circle meet at P

We have to prove  that: (i) ∠PAD = ∠PCB (ii) PA. PB = PC . PD.

ICSE Avichal publication
Understanding ICSE Mathematics
Question 20(b)

circlesml aggarwal solution
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      ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 15 Circles Ex 15.1 Q20.3
      ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 15 Circles Ex 15.1 Q20.4

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