Find the value of p for which the roots of the equation px(x – 2) + 6 = 0, are equal.
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Find the value of p for which the roots of the equation px(x – 2) + 6 = 0, are equal.
px(x-2)+6=0
px²-2px+6=0
After comparing with ax²+bx+c=0
a=p, b= -2p & c= 6
Because our roots are real and equal
∴ D= 0
b²-4ac= 0
(-p)²- 4(p)(6)= 0
P²-24p= 0
P(p-24)= 0
∴p= 0, p= 24