Adv
Deepak Bora
  • 0
Newbie

Quadratic equations

  • 0

Find the value of p for which the roots of the equation px(x – 2) + 6 = 0, are equal.

Share

1 Answer

  1. px(x-2)+6=0

    px²-2px+6=0

    After comparing with ax²+bx+c=0

    a=p, b= -2p   & c= 6

    Because our roots are real and equal

    ∴ D= 0

    b²-4ac= 0

    (-p)²- 4(p)(6)= 0

    P²-24p= 0

    P(p-24)= 0

    ∴p= 0, p= 24

    • 0
Leave an answer

Leave an answer

Browse

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Captcha Click on image to update the captcha.

Related Questions