0 Deepak BoraNewbie Asked: July 10, 20202020-07-10T20:16:49+05:30 2020-07-10T20:16:49+05:30In: CBSE Quadratic equations 0 Find the value of p for which the roots of the equation px(x – 2) + 6 = 0, are equal. Share Facebook 1 Answer Voted Oldest Recent Deepak Bora Newbie 2020-07-13T17:48:05+05:30Added an answer on July 13, 2020 at 5:48 pm px(x-2)+6=0 px²-2px+6=0 After comparing with ax²+bx+c=0 a=p, b= -2p & c= 6 Because our roots are real and equal ∴ D= 0 b²-4ac= 0 (-p)²- 4(p)(6)= 0 P²-24p= 0 P(p-24)= 0 ∴p= 0, p= 24 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions 30. A well of diameter 2 m is dug 14 m deep. The earth taken out of it ... 29. A 16 m deep well with diameter 3.5 m is dug up, and the earth from it ... 28. A path 2 m wide surrounds a circular pond of diameter 40 m. How many cubic meters ... 27. A spherical ball of radius 3 cm is melted and recast into three spherical balls. The radii ... 26. A hollow sphere of internal and external radii 2 cm and 4 cm, respectively, is melted into ...

px(x-2)+6=0

px²-2px+6=0

After comparing with ax²+bx+c=0

a=p, b= -2p & c= 6

Because our roots are real and equal

∴ D= 0

b²-4ac= 0

(-p)²- 4(p)(6)= 0

P²-24p= 0

P(p-24)= 0

∴p= 0, p= 24