This question is from trigonometry topic trigonometric ratios on complementary angles in which we have been asked to prove that sinθ cos(90° − θ) + cosθ sin(90°- θ) = 1
RS Aggarwal, Class 10, chapter 12, question no 5(i).
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sinθ.cos(90°−θ)+cosθsin(90°−θ)
=sinθ.sinθ+cosθcosθ
=sin²θ+cos²θ
=1