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Rajan@2021
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Asked: 2021-04-08T17:04:53+05:30 In:

Prove that: cot12° cot38° cot52° cot60° cot78° = 1/√3

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This question is from trigonometry topic -trigonometric ratios on complementary angles in which we have been asked to prove that cot12° cot38° cot52° cot60° cot78° = 1/√3

RS Aggarwal, class 10, chapter 12, question no 6(ii)

class 10 cbsers aggarwaltrigonometric ratios
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    1. Guru
      Prove that: cot12° cot38° cot52° cot60° cot78° = 1/√3

      Hope it helps you.

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