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Rajan@2021
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Prove that: cosec(65°+θ) – sec(25°-θ) – tan(55-θ) + cot(35°+θ) = 0

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This question is from trigonometry topic -trigonometric ratios on complementary angles in which we have been asked to prove that cosec(65°+θ) – sec(25°-θ) – tan(55-θ) + cot(35°+θ) = 0

RS Aggarwal, Class 10, chapter 12, question no 7(iv)

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  1. LHS=cosec(65°+θ)sec[90°(65°+θ)]tan[90°(35°+θ)]+cot(35°+θ)
    =cosec(65°+θ)cosec(65°+θ)cot(35°+θ)+cot(35°+θ)
    =0
    =RHS

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