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Rajan@2021
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Asked: 2021-04-08T16:47:27+05:30 In:

Prove that: [cos(90°-θ) sec(90°-θ) tan θ]/[cosec(90°-θ) sin(90°-θ) cot(90°-θ] tan(90°-θ)/cotθ = 2

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This question is from trigonometry topic – trigonometric ratios on complementary angles in which we have to show that [cos(90°-θ) sec(90°-θ) tan θ]/[cosec(90°-θ) sin(90°-θ) cot(90°-θ] tan(90°-θ)/cotθ = 2

RS Aggarwal, Class 10, chapter 12, question no 5(iv)

class 10 cbsers aggarwaltrigonometric ratios
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    1. Guru
      Prove that: [cos(90°-θ) sec(90°-θ) tan θ]/[cosec(90°-θ) sin(90°-θ) cot(90°-θ] tan(90°-θ)/cotθ = 2

      Hope it helps you.

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