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Rajan@2021
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Asked: 2021-04-08T16:51:39+05:30 In:

Prove that: cos(90°-θ)/1+sin(90°-θ) + 1+sin(90°-θ)/cos(90°-θ) = 2cosecθ

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This question is from trigonometry topic -trigonometric ratios on complementary angles in which we have been asked to prove that cos(90°-θ)/1+sin(90°-θ) + 1+sin(90°-θ)/cos(90°-θ) = 2cosecθ

RS Aggarwal, Class 10, chapter 12, question no 5(v)

class 10 cbsers aggarwaltrigonometric ratios
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    1. Guru
      Prove that: cos(90°-θ)/1+sin(90°-θ) + 1+sin(90°-θ)/cos(90°-θ) = 2cosecθ

      Hope it helps you.

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