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Rajan@2021
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Prove that: [cos(90°-θ) sec(90°-θ) tan θ]/[cosec(90°-θ) sin(90°-θ) cot(90°-θ] tan(90°-θ)/cotθ = 2

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This question is from trigonometry topic – trigonometric ratios on complementary angles in which we have to show that [cos(90°-θ) sec(90°-θ) tan θ]/[cosec(90°-θ) sin(90°-θ) cot(90°-θ] tan(90°-θ)/cotθ = 2

RS Aggarwal, Class 10, chapter 12, question no 5(iv)

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