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Rajan@2021
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Asked: 2021-04-08T13:17:05+05:30 In:

Prove that: 7cos55°/3sin35° – [4(cos70°Cosec20°)]/3(tan5°tan25°tan45°tan65°tan85°) = 1

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This question is from trigonometry topic – trigonometric ratios on complementary angles in which we have to prove that 7cos55°/3sin35° – [4(cos70°Cosec20°)]/3(tan5°tan25°tan45°tan65°tan85°) = 1

RS Aggarwal, class 10, chapter 12, question no 4(v).

cbse class 10rs aggarwaltrigonometric ratios
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    1. Guru
      Prove that: 7cos55°/3sin35° – [4(cos70°Cosec20°)]/3(tan5°tan25°tan45°tan65°tan85°) = 1

      Hope it helps you.

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