This is the basic and conceptual question from polynomials in which we have given a equation 3x³+16x²+15x-18 and one of its factor is 2/3 and we have to find the other factor
Kindly give me a detailed solution of this question
RS Aggarwal, Class 10, chapter 2A, question no 21
p(x)=3x3+16x2+15x−18
x=2/3
x−2/3=0
(3x−2)/3=0
⇒3x−2=0
x²+6x+9
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3x−2)3x³+16x²+15x−18
3x³−2x²
(−) (+)
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18x²+15x−18
18x²−12x
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27x−18
27x−18
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0
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x²+6x+9
x²+3x+3x+9
x(x+3)+3(x+3)
(x+3)(x+3)
zeroes
x+3=0 x+3=0
x=−3 x=−3
Zeroes of p(x)=−3,−3,2/3