ICSE Board Question Based on Equation of a Straight Line Chapter of M.L Aggarwal for class10
Here a triangle ABC is given with their coordinates
You have to find the equation of the median through A.
This is the Question Number 23, Exercise 12.1 of M.L Aggarwal.
Deepak BoraNewbie
In traingle ABC, A (3, 5), B (7, 8) and C (1, – 10). Find the equation of the median through A.
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Given,
∆ABC and their vertices A (3, 5), B (7, 8) and C (1, – 10).
And, AD is median
So, D is mid-point of BC
Hence, the co-ordinates of D is ([7 + 1]/2, [8 – 10]/2) = (4, -1)
Now,
Slope of AD, m = y2 – y1/ x2 – x1
m = (5 + 1)/ (3 – 4) = 6/-1 = -6
Thus, the equation of AD is given by
y – y1 = m (x – x1)
y + 1 = -6 (x – 4)
y + 1 = -6x + 24
⇒ 6x + y – 23 = 0