In the given figure we have given length of sides of the triangle in terms of X and we need to find the value of X by using the properties of similarities
ML Aggarwal Avichal Publication Class 10, Similarity, Chapter 13ii, question no 2i
Rajan@2021Guru
In the given fig. DE ∥ BC. If AD = x, DB = x – 2, AE = x + 2 and EC = x – 1, find the value of x.
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In Δ ABC, DE ∥ BC
∴AD/DB=AE/EC
(By basic proportionality theorem)
⇒x/x−2x=x+2/x-1
⇒x(x−1)=(x+2)(x−2)
⇒x^2−x=x^2−4
⇒x=4.