How i solve the problem of class 10th math of exercise 6.3 of triangles chapter, because it is very important for board exams, so please guide me the best way to solve the problem In the figure, if ΔABE ≅ ΔACD, show that ΔADE ~ ΔABC.
Share
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Given, ΔABE ≅ ΔACD.
∴ AB = AC [By CPCT] ……………………………….(i)
And, AD = AE [By CPCT] ……………………………(ii)
In ΔADE and ΔABC, dividing eq.(ii) by eq(i),
AD/AB = AE/AC
∠A = ∠A [Common angle]
∴ ΔADE ~ ΔABC [SAS similarity criterion]