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Rajan@2021
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Asked: 2021-03-25T13:43:11+05:30 In:

In the figure given below, E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that △ABE∼△CFB.

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In the figure given below, E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that △ABE∼△CFB.

I came across a question from similarity chapter in which I found difficulty in solving the problem in which we are to prove that  △ABE∼△CFB if E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F.

ML Aggarwal Avichal Publication class 10, similarity, question no 16a

class 10ml aggarwalsimilarity
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      In △ABE and △CFB,
      ∠ABE=∠CFB (Alternate angles)
      ∠BAE=∠BCF (opposite angles of a parallelogram)
      ∴ By AA criterion of similarity, △ABE ∼ △CFB

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