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Rajan@2021
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In the figure given below, E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that △ABE∼△CFB.

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I came across a question from similarity chapter in which I found difficulty in solving the problem in which we are to prove that  △ABE∼△CFB if E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F.

ML Aggarwal Avichal Publication class 10, similarity, question no 16a

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  1. In ABE and CFB,
    ABE=CFB (Alternate angles)
    BAE=BCF (opposite angles of a parallelogram)
     By AA criterion of similarity, ABE  CFB

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