Rajan@2021Guru
In the figure below AB, CD and EF are parallel lines. Given AB= 7.5 cm, DC= y cm. EF = 4.5 cm, BC= x cm and CE = 3 cm. Calculate the values of x and y.
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Consider △ACB△ACB and △CEF△CEF
Both triangles are similar
∴ABEF=x3∴ABEF=x3
⇒7.54.5=x3⇒7.54.5=x3
x=7.54.5×3x=7.54.5×3
∴x=5∴x=5cm
Consider △BCD△BCD and △BFE△BFE
xy=x+34.5xy=x+34.5
5y=5+34.55y=5+34.5
⇒y=5×4.58⇒y=5×4.58
∴y=4516∴y=4516cm