For class 10th students, of chapter triangles exercise 6.3, this is very tough question so please help to solve this question in easy way In the fig.6.36, QR/QS = QT/PR and ∠1 = ∠2. Show that ΔPQS ~ ΔTQR
Share
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
In ΔPQR,
∠PQR = ∠PRQ
∴ PQ = PR ………………………(i)
Given,
QR/QS = QT/PRUsing equation (i), we get
QR/QS = QT/QP……………….(ii)
In ΔPQS and ΔTQR, by equation (ii),
QR/QS = QT/QP
∠Q = ∠Q
∴ ΔPQS ~ ΔTQR [By SAS similarity criterion]