-1 Deepak BoraNewbie Asked: July 26, 20202020-07-26T21:37:44+05:30 2020-07-26T21:37:44+05:30In: CBSE In Figure 4, a square OABC is inscribed in a quadrant OPBQ. If OA = 15 cm, find the area of the shaded region. (Use π = 3·14) -1 CBSE 10th Class past year question paper Year 2019 SET 1, Code Number- 30/2/1 Question number – 18 (a) cbse 10th classncert class 10thprevious year paper Share Facebook 1 Answer Voted Oldest Recent Deepak Bora Newbie 2020-07-29T07:24:59+05:30Added an answer on July 29, 2020 at 7:24 am Radius of quadrant = OB = √ { (15)² + (15)² } = 15 √2 cm Shaded area = Area of quadrant – Area of square = 1/4 (3.14) { ( 15 √2)² – 15² } = 128.25 cm² 2 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Visual Text Save my name, email, and website in this browser for the next time I comment. Related Questions The diameter of a circle is 10 cm. Find the length of the arc, when the corresponding central ... A cylindrical vessel with internal diameter 10 cm and height 10.5 cm is full of water. A solid ... A solid metallic sphere of diameter 28 cm is melted and recast into a number of smaller cones, ... A milk container is made of metal sheet in the shape of frustum of a cone whose volume ... A bucket is in the form of a frustum of a cone with a capacity of 12308.8 cm³ ...
Radius of quadrant = OB = √ { (15)² + (15)² } = 15 √2 cm
Shaded area = Area of quadrant – Area of square
= 1/4 (3.14) { ( 15 √2)² – 15² }
= 128.25 cm²