CBSE 10th Class past year question paper
Year 2019
SET 1, Code Number- 30/2/1
Question number – 18 (a)
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Radius of quadrant = OB = √ { (15)² + (15)² } = 15 √2 cm
Shaded area = Area of quadrant – Area of square
= 1/4 (3.14) { ( 15 √2)² – 15² }
= 128.25 cm²