CBSE 10th Class past year question paper
Year 2019
SET 1, Code Number – 30/2/1
Question number – 15
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∆AOD ≅ AOC [SAS]
∠1 = ∠2
Similarly ∠4 = ∠3
∠1 + ∠4 =∠2 + ∠3 = 1/2 (180°)
∠2 + ∠3 = 90° or
∠AOB = 90°