Deepak Bora
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In the given figure, from an external point P, two tangents PQ and PR are drawn to a circle of radius 4 cm with Centre O. If ∠QPR = 90° , then length of PQ is

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CBSE 10th Class Mathematics
Past year question paper
Year 2020
SET 1, Code Number  – 30/2/1
Question Number –  10
Tangent and circle relation
Pythagoras rule


1 Answer

  1. This answer was edited.

    Looking to the figure, we can understand that OQ is perpendicular to QP,
    Similarly, OR is perpendicular to PR.

    consider the tangents PQ and PR, we get,
    PQ = PR……..(tangent from a same point that is P)

    AC = BC = 4 cm ………..(radius of the circle)

    By considering all the above points, we can prove it that it is a square
    So, PQOR is a square.
    So since it is a square, so all the sides are same,
    OQ = OR = RP = QP

    ∴ QP = 4 cm



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