0 Deepak BoraNewbie Asked: July 26, 20202020-07-26T20:07:42+05:30 2020-07-26T20:07:42+05:30In: CBSE In Figure 2, DE II BC. Find the length of side AD, given that AE = 1·8 cm, BD = 7·2 cm and CE = 5·4 cm. 0 CBSE 10th Class past year question paper Year 2019 SET 1, Code Number – 30/2/1 Question number – 6 (b) cbse 10th classncert classprevious year paper Share Facebook 1 Answer Voted Oldest Recent Deepak Bora Newbie 2020-07-28T19:53:44+05:30Added an answer on July 28, 2020 at 7:53 pm DE II BC AD/BD = AE/CE AD/7.2=1.8/5.4 AD = ( 7.2 × 1.8 ) / 5.4 ∴ AD = 2.4 cm. -5 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Visual Text Save my name, email, and website in this browser for the next time I comment. Related Questions A hemispherical tank, full of water, is emptied by a pipe at the rate of 25/7 litres per ... The radius and height of a solid right-circular cone are in the ratio of 5 : 12. If ... Find the mode of the following distribution Check whether 12∧n can end with the digit 0 for any natural number n. 12∧n = (2 × ... The distance between the points (m, -n) and (-m, n) is
DE II BC
AD/BD = AE/CE
AD/7.2=1.8/5.4
AD = ( 7.2 × 1.8 ) / 5.4
∴ AD = 2.4 cm.