Home/ Questions/Q 11798
In Process
Adv
AnilSinghBora
  • 0
Guru
Asked: 2021-08-12T14:42:48+05:30 In:

In Fig. 9.27, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (ii) ar(AEDF) = ar(ABCDE) Q.11(2)

  • 0
In Fig. 9.27, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (ii) ar(AEDF) = ar(ABCDE) Q.11(2)

Give me the best way for solving the question of class 9th of Areas of Parallelograms and Triangles of exercise 9.3 of math. Give me the easiest way for solving this question in simple way of question no. 11(2) In Fig. 9.27, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (ii) ar(AEDF) = ar(ABCDE

area of parallelograms and triangles ncertbest math ncert solutionexercise 9.3 ncertncert class 9th solution
Share

    1 Answer

    1. Guru
      1. △ACB and △ACF lie on the same base AC and between the same parallels AC and BF.

      ∴ar(△ACB) = ar(△ ACF)

      1. ar(△ACB) = ar(△ACF)

      ⇒ ar(△ACB)+ar(△ACDE) = ar(△ACF)+ar(△ACDE)

      ⇒  ar(ABCDE) = ar(△AEDF)

      • 0
    Leave an answer

    Leave an answer

    Browse

    Choose from here the video type.

    Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

    Captcha Click on image to update the captcha.

    Related Questions

    Adv